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Food served at a restaurant should be between38°C and49°C when it is delivered to the customer. The process used to keep the food at the correct temperature has a process standard deviation of2°C and the mean value for these temperature is23. What is the process capability of the process?
A. Cp=5
B. Cp=1.66
C. Cp=0..88
D. Cp=1.22
I believe the answer is choice (C) 0.88
Cp = ( USL - LSL) /6*STD = (49-38)/6*2 =11/12 =0.92
Agreed with the answer given by Mr. Ayoub Tartir
Agreed with Mr. Ayoub Tartir answer
I agree with Mr.Ayoub's answer
Cpk is an index (a simple number) which measures how close a process is running to its specification limits, relative to the natural variability of the process. The larger the index, the less likely it is that any item will be outside the specs.” Neil Polhemus
This is how to calculate the process capability
Cp is the ratio between the customer acceptable tolerance and6 standard deviations.
The customer tolerance is the differennce between the Upper Standard Limit and the Lower Standard Limit.
Then in our case , Cp= (49-38):6 x 2=11:12=0.91
D. Cp=1.22
should be the correct answer.
answer option >>>>>>>>>>>> D. Cp=1.22
You are an expert, I am endorsing your answer Mr. LABIB KOOLI
Agree with Tartir ................................................
With the above given conditions using the upper limit, lower limit, mean and standard deviation the potential Cp is0.917 and the actual CpK is2.5.
