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For Class C address the host portion is2^8 or256. Out of this1 address is used for network address and the other for broadcast address.So , (2^8) -2 =256-2
which is254 devices
256 ip address .254 (Usabale) ip address can be assigned to hosts .. because the first ip addres will be assigned to the gateway and the last ip address will be assigned to broadcasting in the subnet area . :)
hosts=devices=2^h
in class c default hosts are8
ie=2^8=256
therefore valid hosts=2^h-2
=2^8-2
=256-2
=254
Therefore254 DEVICES is needed in the network of IP address of192.168.1.1 with Subnet Mask of255.255.255.255.0
It's256 devices with the IP Range from192.168.1.1-256.
there is256 device connected in class c
can used.
.1 is gateway
. is last host IP.
