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The question is valid. The question asked that 192.168.1.255 is a host of /20 network. Here we need to think CIDR and VLSM.
192.168.0.0/24 = 192.168.0.0 - 192.168.0.255 = 256
192.168.0.0/23= 192.168.0.0 - 192.168.1.255 = 512
192.168.0.0/22= 192.168.0.0 - 192.168.3.255 =1024
192.168.0.0/21= 192.168.0.0 - 192.168.7.255 =2048
192.168.0.0/20= 192.168.0.0 - 192.168.15.255 =4096
Now we find the range of 192.168.0.0/20 which starts from 192.168.0.0 and ends at 192.168.15.255
Network Address: 192.168.0.0
Broadcast Address: 192.168.15.255
Between 192.168.0.0 to 192.168.15.255 all are usable host. It means 4094 usable host. 192.168.1.255 is also a host in this range.
/ =...0. Multiply this bit by bit to..1.
=..0.0 -> first network address
We only care on the third octet which is being subnetted by4bits,
Adding1 to the4th bit from the left will result to the next network,
=
Which means by adding we will get the other networks(0,,,...,)
1st network =..0.0
2nd network =...0
.
.
th network =...0
Clearly the host(..1.) falls in the first network.
The broadcast address can be calculated by dimishing1 from the last octet of the next network address
Which is equal to .../
192.168.1.255/20
255.255.240.0 11111111.11111111.11110000.00000000 /20
Host = (2 powers 4) -2 = 14 note Number 4 is number of ones 11110000
Sunbet = 2 power 4 = 16 note Number 4 is number of zeros 11110000
First network 192.168.1.1 second network 192.168.1.16
First Host 192.168.1.2 First Host 192.168.1.17
Last host 192.168.1.14 Last host 192.168.1.30
Broadcast domain 192.168.1.15 Broadcast domain 192.168.1.31
Now increase number of first network like this :
16-32-48-64 ....... to 240 - 256 -------> this is last rang
the Broadcast domain 192.168.1.255
Wrong Question :)
easy to know
http://www.subnet-calculator.com/
The broadcast address is
...
the answer is... the network address is..0.0/
Broadcast address of 192.168.1.255 /20 is 192.168.15.255
It will be...0. Hope you have right answer.
