Why the circuit Current (I) decrease, when Inductance (L) or inductive reactance (XL) increases in inductive circuit?

Question

muhammad arif · Answer

We know that, I = V / R, but in inductive circuit, I = V/XLSo Current in inversely proportional to the Current ( in inductive circuit.Let's check with an example.. Suppose, when Inductance (L) =0.02H

V=220, R=10 Ω, L=0.02 H, f=50Hz.

XL =2πfL =2 x3.1415 x50 x0.02 =6.28 Ω

Z = √ (R2+XL2) = √ (102 +6.282) =11.8 Ω I = V/Z =220/11.8 = 18.64 A

Vaishnavi Anil · Answer

V=Ldi/dt

where,

V=voltage across inductor

L=inductance

i=current across inductor

From the above relation ,it is understood that on integrating this equation, we obtain that current i is inversely proportional to the inductance L. Thus, when inductance increases, current increases.

Now, inductive reactance XL and inductance L are related by the equation:

XL=2πfL

which means that the two are directly related , so current also increases if XL increases.

Liji SAJI JOB · Answer

The relation between current,voltage across the inductor and inductance is given by the formula:
V=Ldi/dt
V/L=di/dt.  -(1)
From eq1 we get L is inversely proportional to current for a constant voltage therefore when L increases current decreases.

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Why the circuit Current (I) decrease, when Inductance (L) or inductive reactance (XL) increases in inductive circuit?

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