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WHAT IS THE QUANTITY OF CEMENT FOR 1 M3 OF PLASTERING 1.:6 RATIO ?

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Question added by dijo kuriakose adukalil , JUNIOR ENGINEER , talal adham partners co
Date Posted: 2014/09/03
Muhammad Ayub Khan
by Muhammad Ayub Khan , Project Control Manager , M/S Awal Dad & Brothers

Usually for Plaster quantities get in units ( SM/SFT or Sqr.Yard)  

Material Calculation Method:

For Example: 

Plaster Ratio (1:6)

 

Solution:

 

Unit of Rate                            :10.00 Sq.M

Thickness of Plaster             :2 cm

Wet Vol of Mortar                  :10x2/100      =0.20 Cu.M

Dry Vol of Mortar                  :  0.20 x1.27  =0.254 Cu.m

Ratio of mortar                     :1:6

Sum of Ratio                         :1+6 =7

 

Material Required:

1. Cement Qty                       :1/7 x0.254           =0.036 Cu.M

                                               :0.036 /0.035        =1.02 bags

 

2. Sand Qty                          :6/7x0.254            =0.22 Cu.m

 

Deleted user
by Deleted user

Usually Plastering has the following calculations.

 

Cement = {1 / (1+6)} x {1.25 x1.25} x {1440 /50} ==6.5 Bags

Sand =  {6 / (1+6)} x {1.25 x1.25} x1.07 ==1.4 Cum

 

While calculating, it is multiplied by25 % each to compensate Dry to Wet volume conversion & for wastage part (some companies use lesser or higher percentages also) and1440 is density of cement and divided by50 to get the answer in bags.

 

While calculating sand, additionally7% is added to compensate bulking of sand.

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