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Subnet for the host 128.64.32.16/20 is 128.64.32.0
subnet mask of this will be255.255.240.0
i think the subnet mask is 255.255.240.0
the subnet mask128.64.32.16/20 is255.255.240.0
128.64.32.16 /20 which is equal to255.255.240.0
255.255..
128.64 ..
Use AND operator between above two addresses we get
128.64.. which is equal to128.64.32.0
The Subnet mask is Class B