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Father is aged 3 times more than his son. After 8 yrs,he would be 2.5 times of Son's age. After further 8 yrs,how many times would he be of Son's age?

A.1.25 times

B.1.5 times

C.2 times

D.2.25 times

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Question added by CA SHAHAD AC , Accounts Associates , UCWF Facilities Management LLC
Date Posted: 2015/04/09

D.2.25yrs.

x=3x

x+8=2.5(x+8)

 

Lakshmi Anuradha
by Lakshmi Anuradha , Test Analyst , RAK Bank

Let present age of father: x

Let present age of son: y

 

Equations will be:

x = 3y

(x+8) = 2.5(y+8)

solving these both,

answer will be:

 

2.25 times

SAJIMON THOMAS
by SAJIMON THOMAS , Accountant , Lamar Interiors for Furniture co

let the age of son be X then father is3X

after8 years son is X+8 father will be2.5(X+8)

 

and the answer is2. times

Nidal Sabi
by Nidal Sabi , Maths teacher , Ministère de l'éducation

Hey M. Shahad,

My answer is2.2 times

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