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The best way to solve these kinds of Qs is to divid the numbers into groups. Like taking the lowest number zero and add it to highest number100 will give a result of100 for the first group then you do the same with the second lowest and the second highest which are1 and99. By continuing the same for all the groups, you notice all the results end to be100. Then all you have to do is to multiply the100 by50 which is the number of groups and then add50 to the final result since the number50 is not in a group.
Answer :-
(50 x100) +50 =5050
You can use the formula sigma(n)=n(n+1)/2 which gives you 100(101)/2 = 5050
The numbers0 ,1 ,2 ,.............. is a sequential limits to consecutive calculation basis of which only the first Last alone . Ear:
0+1+2+……………… =(+1)(0)/2=/2=.5
