Start networking and exchanging professional insights

Register now or log in to join your professional community.

Follow

How to explain Bernoulli’s theorem? State its application.

user-image
Question added by Faseem Abdulla Kattil Veedu , Lead Instrumentation Engineer/Procurement Engineer , Sinopec Branch Of International Petroleum Coorporation
Date Posted: 2016/03/12
Adnan Ahmad
by Adnan Ahmad , Senior Electrical Engineer , Engro Polymer and Chemicals ( Petrochemical Plant)

The Bernouli theroam is application is wide. it is widely used in Flow measurement techniques.

it explain that when there is a restriction line in fluid flow line a DP (differential pressure)is created.

the DP is the maximum at the veena contract point.the flow measured in the flow line is proportional to the square root of the DP measured where K is a constant.

Q=k 6sq root of DP

Hasan Zainy
by Hasan Zainy , Control / Instrumentation Filed Service Engineer , GE

application is used in flow measurement. such as flow sensing by using pressure difference transmitter

 

 

the idea is put constraint in the flow like orifce in the pipe. so the difference between before and after the orifice.

 

from these pressure the flow can e calculated  

Ibrahim El-Hadidi
by Ibrahim El-Hadidi , Gas Turbine Senior Mechanical Technician , Mellitah Oil & Gas B.V.

Height, Velocity, pressure and density are all considered in Bernoulli's theorem. where the total pressure is summation of static and dynamic pressure. its general observation stated that increase in fluid velocity will lead to decrease of pressure (and opposite is correct) of hydraulic system while passes through venturi model.

  1. Bernoulli's equation: P1+1/2 pV^2+pgh1=P2+1/2 pV2^2+pgh2

Alessandro Puddu
by Alessandro Puddu , Supervisor , Saipem

Bernoulli’s theorem, in fluid dynamics, relation among the pressure, velocity, and elevation in a moving fluid (liquid or gas), the compressibility and viscosity of which are negligible and the flow of which is steady, or laminar.

Mathematically, for unit mass of fluid flowing through a pipe :            P / rho + g x h + 1/2 x V^2 = constant          

More Questions Like This