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There are two people, A and B. Each has an integer. Together, the two integers multiply to either8 or. A: "With the number I have, I do not know the number you have." B: "I still don’t know what you have either." A: "I know what you have now." B: "Oh mate, I know what you have too." What are the numbers that B could have?
lets discuss the the possibilities
if "A" have the number 1 then "B" will have 8 or 16 and the multiply will be either 8 or 16, so "A" dont know what is the number of "B" 8 or 16
if "A" have the number 2 the possibilities for "B" is 4 or 8if "A" have the number 4 the possibilities for "B" is 2 or 4if "A" have the number 8 the possibilities for "B" is 1 or 2if "A" have the number 16 the possibility for "B" is just 1
how we will do it by programming:we will make a counter start with 0 to know the number of the possibilities of "B"then we will check the counter value.the value will changed if the multiply is correct.if the value was 1 we will print the value of "A" and "B"else the value should be 2 and we will do nothing.
Here is the code in C++ language
////////////////////////////////////////#include <iostream>using namespace std;void main(){ int Count; for (int a=1;a<=16;a++){ Count=0; for (int b=1;b<=16; b++){ if (a*b==16||a*b==8){ Count++; } } if (Count ==1){ cout <<"know"<<endl; for (int b=1;b<=16; b++){ if (a*b==16||a*b==8)cout <<a<<"\\t"<<b<<endl; } } else cout<<"dont know"<<endl; }}///////////////////////////////////
I put two strings ("know", "dont know") to know the condition if it was true or false
if any one have another way to solve I am interested to know it.
