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How can controlled frequency bandwidth of op-amp output with respect of input?

Consider I gave input of5Mhz bandwidth of analog signal op-amp input and the i need2Mhz bandwidth of output

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Question added by Muthu Krishnan , Lab engineer , vtitan corporation pvt
Date Posted: 2014/01/11
ramdani noureddine
by ramdani noureddine , chef de division technique , algerie télécom

Propriété Ordre de grandeur Bipolaire (LM741)35,36 BiFET (TL081)37,38 Bimos (CA3140)39 Cmos (LMC6035)40 Amplification Adiff=Vs/(V+-V-) > 105202*1052*105105106 Gain Gdiff=20.log(Adiff) > 10020106106100120 Impédance d'entrée Re (Ω) > 105232*10610121,5*1012 > 1013 Impédance de sortie Rs (Ω) < 2007510060 Fréquence de coupure f110 Hz41 ~20 Hz Courants de fuite I+, I- < 500 nA 80 nA 30 pA 10 pA 0,02 pA Tension d'offset Voff (mV) < 101380,5 TRMC Gdiff/Gmc (dB) > 702090869096 Tension de bruit (nV/{\\displaystyle {\\sqrt {Hz}}}\\sqrt{Hz})42184027

Rostom El Baz
by Rostom El Baz , ICT-Project Engineer , Alghanim International

If you want to apply such relation by mean of controlling the frequency of output regarding the input frequency 

As the closed loop gain and the small signal bandwidth of an op amp are closely related, the parameter ‘Gain Bandwidth Product’ is often used to better describe the possible combinations of gain and bandwidth. The graph of the open loop frequency response in Fig.6.4.1 therefore, plots all those points where voltage gain x bandwidth =1.4 million(Hz). For example,140kHz bandwidth multiplied by a voltage gain of10 also gives a Gain Bandwidth Product of:

10 x140kHz =1.4MHz

Note that bandwidth indicated by the Gain Bandwidth Product applies to small signals, but when large AC signals are involved, especially signals with fast rising and falling edges, the bandwidth may be further reduced by the Slew Rate. Then the Power Bandwidth becomes more relevant.

   

For more assiatance plesae visit:http://www.learnabout-electronics.org/Amplifiers/amplifiers64.php

or 

http://en.wikipedia.org/wiki/Operational_amplifier

 

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