What is Calculation of electrical cable size?

CABLE.SIZING.FORMULA::2*L*I/(K*Vd)...............FOR.SINGLE.PHASE I……..LOAD.CURRENT.=160….AMPS L…….LENGTH.OF.THE.CABLE.= 200 METERS K……CONDUCTIVITY.OF.COPPER.=.58,AND.CONDUCTIVITY.OF.ALUMINUM.=36 Vd:- VOLTAGE DROP3% OF230 VOLTS=6.9 VOLT AND FOR3PH.3% OF400VOLT=12 VOLTS APPLY.THE.FORMULA:- AREA(mm2) =2 * L * I/(K * Vd) =2 *200*160/(58*6.9) =159.92 mm2 required(FOR SINGLE PHASE) AREA(mm2) =1.732*L*I/(K*Vd) =1.732*200*160/(58*12) =79.6 mm2 required(FOR THREE PHASE)

you should use relations and formula  in standards and be aware of voltage drop and heat effect. each cable has its own detaile and Specifications. 

it is a right answer hazem