A bat and a ball costs $1.10. If the bat costs $1.00 more than the ball, how much does the ball cost?

The ball cost $0.05/

Details:

because the bat and ball together are of $1.10

you have also mentioned that the bat is  $1 more than the ball cost.

it means if the ball is of $.05 then the bat will be of ($1 + (the cost of ball)) = $1 + $.05 = $1.05

>>bat and ball together equals to = bat($1.05) + ball($0.05) = $1.10

Total cost = $1.10 (including bat and ball - bat -$1.00 + ball - $0.10) ,because ball cost is high $1.00 than ball , so ball cost is $0.10

Bat + Ball =1,10

Bat = Ball +1,00

=> substitute the2nd equation in the first and you get

Ball +1,00 + Ball =1,10 <=>2 * Ball =1,10 -1,00 <>2 * Ball =0,10 <=> Ball =0,10 /2 <=> Ball =0,05

=> Now for the end results:

Ball =0,05

Bat =1,10 - Ball <=> Bat =1,10 -0,05 <=> Bat1,05

Let's put some name on what we are looking for:

1- P' is the price of the ball. 2- P'' is the price of the bat.  3- P is the total cost.

According to the question:  P=1.10=P'+P"=P'+(P'+1)

  <=> P'+P'+1=1.10

  <=>2P'+1=1.10

  <=> P'= (1.1-1)/2

  <=> P'=.05

The ball costs0.05$, the bat1.05$. (as verification the addition of the2 prices equals1.1$)

The ball costs $01.10

The ball would cost $0.10

the bat costs $1.05 and the ball cost $.05

The Ball cost should be0.05"

From a pure mathmatic point of view the ball, as the information provided, cost $0.10 but unless the the ball or bat was on an offer (Buy1 get the other for a less price)

it will be0.05 

1.05 (Bat) +0.05 (Ball) =1.10

my ans is1.10