How can we calculate age from a given date in years, months and days using PHP 5.2?

Use this code: (read the comments)

<?php

// to tranform the number of days to the number of years , we need to know if a given year is leap or not

function is_leap_year($year)

{

return ((($year %4) ==0) && ((($year %100) !=0) || (($year %400) ==0)));

}

// this function takes in argument a date: format: YYYY-MM-DD

// and returns the age in years , months and days

function age($date)

{

$age_year=0;

$date_unix=strtotime($date);

// the age in days

$time_actual=time();

$age_seconds=$time_actual-$date_unix;

$nb_days=((($age_seconds/60)/60)/24);

// this is the year of birth

$year_birth=date('Y',$date_unix);

$stop=false;

while(($nb_days>0) && (!($stop)))

{

$next_year=$year_birth+1;

if(is_leap_year($next_year))

{

if($nb_days>=366)

{

$nb_days=$nb_days-366;

$age_year++;

}//

else $stop=true;

}//

else

{

if($nb_days>=365)

{

$nb_days=$nb_days-365;

$age_year++;

}//

else $stop=true;

}//

}//

$tab['year']=$age_year;

$tab['days']=$nb_days;

// here you should make another loop over the number: nb_days to transform it to the number of months ans days

// i dont have time now because i should continue my work

return($tab);

}//

// example

print_r(age(''));

?>