How to calculate cooling tower blowdown ratio?

M = Make-up water in m3/hr

C = Circulating water in m3/hr

D = Draw-off water in m3/hr

E = Evaporated water in m3/hr

W = Windage loss of water in m3/hr

X = Concentration in ppmw (of any completely soluble salts à usually chlorides)

XM = Concentration of chlorides in make-up water (M), in ppmw

XC = Concentration of chlorides in circulating water (C), in ppmw

Cycles = Cycles of concentration = XC / XM ppmw = parts per million by weight

A water balance around the entire system is:

M = E + D + W

Since the evaporated water (E) has no salts, a chloride balance around the system is:

M (XM) = D (XC) + W (XC) = XC (D + W)

and, therefore:

XC / XM = Cycles = M / (D + W) = M / (M û E) = 1 + {E / (D + W)}

From a simplified heat balance around the cooling tower:

(E) = (C) (ΔT) (cp) / HV

where: HV = latent heat of vaporization of water = ca. 2260 kJ / kg

ΔT = water temperature difference from tower top to tower bottom, in °C

cp = specific heat of water = 4.184 kJ / kg / °C

Windage losses (W), in the absence of manufacturer's data, may be assumed to be: W = 0.3 to 1.0 percent of C for a natural draft cooling tower

W = 0.1 to 0.3 percent of C for an induced draft cooling tower

W = about 0.01 percent or less of C if the cooling tower has windage drift eliminators

Concentration cycles in petroleum refinery cooling towers usually range from 3 to 7. In some large power plants, the cooling tower concentration cycles may be much higher.

(Note: Draw-off and blowdown are synonymous. Windage and drift are also synonymous.)

Source: http://www.eng-tips.com/faqs.cfm?fid=1152

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